inverse permutation

Let $w \in S_{n}$ be a permutation. Then, its inverse permutation is the inverse as a group element.

One way you can get it is by taking the 2-line notation, flipping the top and the bottom row, and then rearranging the terms so the top row is in order.
For example, suppose we have the permutation $w = 3, 5, 2, 4, 7, 1, 6$ . Then,

w^{- 1} = (\begin{matrix} 3 & 5 & 2 & 4 & 7 & 1 & 6 \\ 1 & 2 & 3 & 4 & 5 & 6 & 7 \end{matrix}) ⇝ (\begin{matrix} 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ 6 & 3 & 1 & 4 & 2 & 7 & 5 \end{matrix})